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-.2x^2+1.75x+2.5=0
We add all the numbers together, and all the variables
-0.2x^2+1.75x+2.5=0
a = -0.2; b = 1.75; c = +2.5;
Δ = b2-4ac
Δ = 1.752-4·(-0.2)·2.5
Δ = 5.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.75)-\sqrt{5.0625}}{2*-0.2}=\frac{-1.75-\sqrt{5.0625}}{-0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.75)+\sqrt{5.0625}}{2*-0.2}=\frac{-1.75+\sqrt{5.0625}}{-0.4} $
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